Base | Representation |
---|---|
bin | 100111101010011000011… |
… | …0111010101110000101001 |
3 | 201022010022212000212212220 |
4 | 1033110300313111300221 |
5 | 1203302410111441131 |
6 | 15332114401024253 |
7 | 1101555110433504 |
oct | 117246067256051 |
9 | 21263285025786 |
10 | 5451133312041 |
11 | 18118a370a02a |
12 | 740571625089 |
13 | 3070691b7661 |
14 | 14bb9c9aa13b |
15 | 96be3225e96 |
hex | 4f530dd5c29 |
5451133312041 has 16 divisors (see below), whose sum is σ = 7387560790848. Its totient is φ = 3574401105600.
The previous prime is 5451133311989. The next prime is 5451133312049. The reversal of 5451133312041 is 1402133311545.
It is not a de Polignac number, because 5451133312041 - 221 = 5451131214889 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5451133311993 and 5451133312011.
It is not an unprimeable number, because it can be changed into a prime (5451133312049) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5571346 + ... + 6476276.
It is an arithmetic number, because the mean of its divisors is an integer number (461722549428).
Almost surely, 25451133312041 is an apocalyptic number.
It is an amenable number.
5451133312041 is a deficient number, since it is larger than the sum of its proper divisors (1936427478807).
5451133312041 is a wasteful number, since it uses less digits than its factorization.
5451133312041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 937912.
The product of its (nonzero) digits is 21600, while the sum is 33.
Adding to 5451133312041 its reverse (1402133311545), we get a palindrome (6853266623586).
The spelling of 5451133312041 in words is "five trillion, four hundred fifty-one billion, one hundred thirty-three million, three hundred twelve thousand, forty-one".
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