54511614013433 has 4 divisors (see below), whose sum is σ = 54511647422208. Its totient is φ = 54511580604660.

The previous prime is 54511614013429. The next prime is 54511614013457. The reversal of 54511614013433 is 33431041611545.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 54511614013433 - 2² = 54511614013429 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (54511614043433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14124041 + ... + 17564502.

It is an arithmetic number, because the mean of its divisors is an integer number (13627911855552).

Almost surely, 2^{54511614013433} is an apocalyptic number.

It is an amenable number.

54511614013433 is a deficient number, since it is larger than the sum of its proper divisors (33408775).

54511614013433 is a wasteful number, since it uses less digits than its factorization.

54511614013433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33408774.

The product of its (nonzero) digits is 259200, while the sum is 41.

Adding to 54511614013433 its reverse (33431041611545), we get a palindrome (87942655624978).

The spelling of 54511614013433 in words is "fifty-four trillion, five hundred eleven billion, six hundred fourteen million, thirteen thousand, four hundred thirty-three".