Base | Representation |
---|---|
bin | 11000110010100010011000… |
… | …01111110000110111010011 |
3 | 21011000101120222121111111012 |
4 | 30121101030033300313103 |
5 | 24121120113023342210 |
6 | 311534532310041135 |
7 | 14324302026465500 |
oct | 1431211417606723 |
9 | 234011528544435 |
10 | 54513004121555 |
11 | 16407920748151 |
12 | 6144b9a9491ab |
13 | 2455728852155 |
14 | d6662cc8a4a7 |
15 | 64801d216305 |
hex | 31944c3f0dd3 |
54513004121555 has 12 divisors (see below), whose sum is σ = 76095703712880. Its totient is φ = 37380345683184.
The previous prime is 54513004121507. The next prime is 54513004121561. The reversal of 54513004121555 is 55512140031545.
54513004121555 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 54513004121555 - 26 = 54513004121491 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 111251028575 + ... + 111251029064.
It is an arithmetic number, because the mean of its divisors is an integer number (6341308642740).
Almost surely, 254513004121555 is an apocalyptic number.
54513004121555 is a deficient number, since it is larger than the sum of its proper divisors (21582699591325).
54513004121555 is a wasteful number, since it uses less digits than its factorization.
54513004121555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 222502057658 (or 222502057651 counting only the distinct ones).
The product of its (nonzero) digits is 300000, while the sum is 41.
The spelling of 54513004121555 in words is "fifty-four trillion, five hundred thirteen billion, four million, one hundred twenty-one thousand, five hundred fifty-five".
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