Base | Representation |
---|---|
bin | 100111101011010011111… |
… | …1000010011100111100001 |
3 | 201022022111000020220001222 |
4 | 1033112213320103213201 |
5 | 1203321002243212423 |
6 | 15333044450104425 |
7 | 1101655434446120 |
oct | 117264770234741 |
9 | 21268430226058 |
10 | 5453130054113 |
11 | 1812728830995 |
12 | 740a2a27b115 |
13 | 3072c6a90b41 |
14 | 14bd0bc57ab7 |
15 | 96cad6933c8 |
hex | 4f5a7e139e1 |
5453130054113 has 4 divisors (see below), whose sum is σ = 6232148633280. Its totient is φ = 4674111474948.
The previous prime is 5453130054101. The next prime is 5453130054121. The reversal of 5453130054113 is 3114500313545.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5453130054113 - 230 = 5452056312289 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5453130054133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 389509289573 + ... + 389509289586.
It is an arithmetic number, because the mean of its divisors is an integer number (1558037158320).
Almost surely, 25453130054113 is an apocalyptic number.
It is an amenable number.
5453130054113 is a deficient number, since it is larger than the sum of its proper divisors (779018579167).
5453130054113 is an equidigital number, since it uses as much as digits as its factorization.
5453130054113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 779018579166.
The product of its (nonzero) digits is 54000, while the sum is 35.
Adding to 5453130054113 its reverse (3114500313545), we get a palindrome (8567630367658).
The spelling of 5453130054113 in words is "five trillion, four hundred fifty-three billion, one hundred thirty million, fifty-four thousand, one hundred thirteen".
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