Base | Representation |
---|---|
bin | 1111110111111100011… |
… | …11011111110011101011 |
3 | 1221010212001022122120121 |
4 | 13323332033133303223 |
5 | 32414020411321403 |
6 | 1054322342504111 |
7 | 54256204006252 |
oct | 7737617376353 |
9 | 1833761278517 |
10 | 545431354603 |
11 | 1a0352864653 |
12 | 8985ba35037 |
13 | 3c58452ac15 |
14 | 1c582c99799 |
15 | e2c437a3bd |
hex | 7efe3dfceb |
545431354603 has 4 divisors (see below), whose sum is σ = 545492162968. Its totient is φ = 545370546240.
The previous prime is 545431354597. The next prime is 545431354607. The reversal of 545431354603 is 306453134545.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 306453134545 = 5 ⋅61290626909.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-545431354603 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 545431354603.
It is not an unprimeable number, because it can be changed into a prime (545431354607) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30390726 + ... + 30408667.
It is an arithmetic number, because the mean of its divisors is an integer number (136373040742).
Almost surely, 2545431354603 is an apocalyptic number.
545431354603 is a deficient number, since it is larger than the sum of its proper divisors (60808365).
545431354603 is an equidigital number, since it uses as much as digits as its factorization.
545431354603 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 60808364.
The product of its (nonzero) digits is 1296000, while the sum is 43.
The spelling of 545431354603 in words is "five hundred forty-five billion, four hundred thirty-one million, three hundred fifty-four thousand, six hundred three".
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