Base | Representation |
---|---|
bin | 11000110011101101011100… |
… | …00100111000000101110001 |
3 | 21011011020121021200100111122 |
4 | 30121312232010320011301 |
5 | 24122300124313443101 |
6 | 312005235021352025 |
7 | 14330226430135136 |
oct | 1431665604700561 |
9 | 234136537610448 |
10 | 54553300140401 |
11 | 16422a19800567 |
12 | 6150965a08615 |
13 | 245947b03a39a |
14 | d685728b258d |
15 | 6490cabc251b |
hex | 319dae138171 |
54553300140401 has 8 divisors (see below), whose sum is σ = 57455284147680. Its totient is φ = 51654391901568.
The previous prime is 54553300140373. The next prime is 54553300140413. The reversal of 54553300140401 is 10404100335545.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 54553300140401 - 214 = 54553300124017 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (54553300140461) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 768905696 + ... + 768976641.
It is an arithmetic number, because the mean of its divisors is an integer number (7181910518460).
Almost surely, 254553300140401 is an apocalyptic number.
It is an amenable number.
54553300140401 is a deficient number, since it is larger than the sum of its proper divisors (2901984007279).
54553300140401 is a wasteful number, since it uses less digits than its factorization.
54553300140401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1537884223.
The product of its (nonzero) digits is 72000, while the sum is 35.
Adding to 54553300140401 its reverse (10404100335545), we get a palindrome (64957400475946).
The spelling of 54553300140401 in words is "fifty-four trillion, five hundred fifty-three billion, three hundred million, one hundred forty thousand, four hundred one".
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