Base | Representation |
---|---|
bin | 11000110101010011011001… |
… | …10011100000100010101011 |
3 | 21011100110220011201012212011 |
4 | 30122221230303200202223 |
5 | 24124144231122041212 |
6 | 312050330451100351 |
7 | 14334205062213463 |
oct | 1432515463404253 |
9 | 234313804635764 |
10 | 54608039643307 |
11 | 16444159828267 |
12 | 615b4a1ba16b7 |
13 | 246169298c3a7 |
14 | d6b086854ba3 |
15 | 64a7316b44a7 |
hex | 31aa6cce08ab |
54608039643307 has 4 divisors (see below), whose sum is σ = 54644469291000. Its totient is φ = 54571609995616.
The previous prime is 54608039643277. The next prime is 54608039643383. The reversal of 54608039643307 is 70334693080645.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 54608039643307 - 219 = 54608039119019 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (54608039643907) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18214821598 + ... + 18214824595.
It is an arithmetic number, because the mean of its divisors is an integer number (13661117322750).
Almost surely, 254608039643307 is an apocalyptic number.
54608039643307 is a deficient number, since it is larger than the sum of its proper divisors (36429647693).
54608039643307 is a wasteful number, since it uses less digits than its factorization.
54608039643307 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 36429647692.
The product of its (nonzero) digits is 39191040, while the sum is 58.
The spelling of 54608039643307 in words is "fifty-four trillion, six hundred eight billion, thirty-nine million, six hundred forty-three thousand, three hundred seven".
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