Base | Representation |
---|---|
bin | 11000110111111110101000… |
… | …00101000110010110110011 |
3 | 21011200021011201112112120122 |
4 | 30123333110011012112303 |
5 | 24132201012423333412 |
6 | 312200452345200455 |
7 | 14343641110510223 |
oct | 1433772405062663 |
9 | 234607151475518 |
10 | 54699966621107 |
11 | 1647a142150295 |
12 | 617527819012b |
13 | 246a252a9c702 |
14 | d716c7640083 |
15 | 64cd11ccc572 |
hex | 31bfd41465b3 |
54699966621107 has 4 divisors (see below), whose sum is σ = 57078226039440. Its totient is φ = 52321707202776.
The previous prime is 54699966621077. The next prime is 54699966621121. The reversal of 54699966621107 is 70112666999645.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 54699966621107 - 212 = 54699966617011 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (54699966921107) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1189129709132 + ... + 1189129709177.
It is an arithmetic number, because the mean of its divisors is an integer number (14269556509860).
Almost surely, 254699966621107 is an apocalyptic number.
54699966621107 is a deficient number, since it is larger than the sum of its proper divisors (2378259418333).
54699966621107 is a wasteful number, since it uses less digits than its factorization.
54699966621107 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2378259418332.
The product of its (nonzero) digits is 264539520, while the sum is 71.
The spelling of 54699966621107 in words is "fifty-four trillion, six hundred ninety-nine billion, nine hundred sixty-six million, six hundred twenty-one thousand, one hundred seven".
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