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54715734433 = 61896979253
BaseRepresentation
bin110010111101010011…
…111101100110100001
312020020020022022010201
4302331103331212201
51344024212000213
641045220025201
73644623032433
oct627523754641
9166206268121
1054715734433
1121228673138
12a730232201
13520ca4c529
142910b56653
1516538996dd
hexcbd4fd9a1

54715734433 has 4 divisors (see below), whose sum is σ = 55612713748. Its totient is φ = 53818755120.

The previous prime is 54715734419. The next prime is 54715734439. The reversal of 54715734433 is 33443751745.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 18228240144 + 36487494289 = 135012^2 + 191017^2 .

It is a cyclic number.

It is not a de Polignac number, because 54715734433 - 25 = 54715734401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (54715734439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 448489566 + ... + 448489687.

It is an arithmetic number, because the mean of its divisors is an integer number (13903178437).

Almost surely, 254715734433 is an apocalyptic number.

It is an amenable number.

54715734433 is a deficient number, since it is larger than the sum of its proper divisors (896979315).

54715734433 is an equidigital number, since it uses as much as digits as its factorization.

54715734433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 896979314.

The product of its digits is 2116800, while the sum is 46.

The spelling of 54715734433 in words is "fifty-four billion, seven hundred fifteen million, seven hundred thirty-four thousand, four hundred thirty-three".

Divisors: 1 61 896979253 54715734433