5471711131 has 4 divisors (see below), whose sum is σ = 5546666152. Its totient is φ = 5396756112.

The previous prime is 5471711123. The next prime is 5471711159. The reversal of 5471711131 is 1311171745.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5471711131 - 2³ = 5471711123 is a prime.

It is a super-2 number, since 2×5471711131² = 59879245402218598322, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5471711093 and 5471711102.

It is not an unprimeable number, because it can be changed into a prime (5471715131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37477401 + ... + 37477546.

It is an arithmetic number, because the mean of its divisors is an integer number (1386666538).

Almost surely, 2^5471711131 is an apocalyptic number.

5471711131 is a deficient number, since it is larger than the sum of its proper divisors (74955021).

5471711131 is an equidigital number, since it uses as much as digits as its factorization.

5471711131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 74955020.

The product of its digits is 2940, while the sum is 31.

The square root of 5471711131 is about 73971.0154790375. The cubic root of 5471711131 is about 1762.1426138270.

Adding to 5471711131 its reverse (1311171745), we get a palindrome (6782882876).

The spelling of 5471711131 in words is "five billion, four hundred seventy-one million, seven hundred eleven thousand, one hundred thirty-one".