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54721336897 = 192880070363
BaseRepresentation
bin110010111101101001…
…010101011001000001
312020020121211221021101
4302331221111121001
51344032130240042
641045540054401
73645021455233
oct627551253101
9166217757241
1054721336897
112123084a377
12a732094401
135210c615b6
1429117b4253
1516541046b7
hexcbda55641

54721336897 has 4 divisors (see below), whose sum is σ = 57601407280. Its totient is φ = 51841266516.

The previous prime is 54721336871. The next prime is 54721336909. The reversal of 54721336897 is 79863312745.

54721336897 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-54721336897 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (54721336807) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1440035163 + ... + 1440035200.

It is an arithmetic number, because the mean of its divisors is an integer number (14400351820).

Almost surely, 254721336897 is an apocalyptic number.

It is an amenable number.

54721336897 is a deficient number, since it is larger than the sum of its proper divisors (2880070383).

54721336897 is a wasteful number, since it uses less digits than its factorization.

54721336897 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2880070382.

The product of its digits is 7620480, while the sum is 55.

The spelling of 54721336897 in words is "fifty-four billion, seven hundred twenty-one million, three hundred thirty-six thousand, eight hundred ninety-seven".

Divisors: 1 19 2880070363 54721336897