Base | Representation |
---|---|
bin | 11000111010110100100010… |
… | …11111010111000110000001 |
3 | 21012000121021022100011220201 |
4 | 30131122101133113012001 |
5 | 24140301023210222440 |
6 | 312313404013205201 |
7 | 14353666306015345 |
oct | 1435322137270601 |
9 | 235017238304821 |
10 | 54797633679745 |
11 | 16507600705a80 |
12 | 6190194790801 |
13 | 2476519172278 |
14 | d763108d9625 |
15 | 65062b2da19a |
hex | 31d6917d7181 |
54797633679745 has 16 divisors (see below), whose sum is σ = 72643123134720. Its totient is φ = 39348358358400.
The previous prime is 54797633679713. The next prime is 54797633679787.
54797633679745 is nontrivially palindromic in base 10.
54797633679745 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 54797633679745 - 25 = 54797633679713 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6305822316 + ... + 6305831005.
It is an arithmetic number, because the mean of its divisors is an integer number (4540195195920).
Almost surely, 254797633679745 is an apocalyptic number.
54797633679745 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
54797633679745 is a deficient number, since it is larger than the sum of its proper divisors (17845489454975).
54797633679745 is a wasteful number, since it uses less digits than its factorization.
54797633679745 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12611653416.
The product of its digits is 25204737600, while the sum is 82.
The spelling of 54797633679745 in words is "fifty-four trillion, seven hundred ninety-seven billion, six hundred thirty-three million, six hundred seventy-nine thousand, seven hundred forty-five".
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