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548082712113 = 3182694237371
BaseRepresentation
bin1111111100111000100…
…01100111111000110001
31221101200211022120022220
413332130101213320301
532434433133241423
61055441414351253
754412000120446
oct7763421477061
91841624276286
10548082712113
111a1493447802
128a27b95b529
133c8b7913111
141c7550699cd
15e3cc0029e3
hex7f9c467e31

548082712113 has 4 divisors (see below), whose sum is σ = 730776949488. Its totient is φ = 365388474740.

The previous prime is 548082712109. The next prime is 548082712157. The reversal of 548082712113 is 311217280845.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 548082712113 - 22 = 548082712109 is a prime.

It is not an unprimeable number, because it can be changed into a prime (548082712613) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 91347118683 + ... + 91347118688.

It is an arithmetic number, because the mean of its divisors is an integer number (182694237372).

Almost surely, 2548082712113 is an apocalyptic number.

It is an amenable number.

548082712113 is a deficient number, since it is larger than the sum of its proper divisors (182694237375).

548082712113 is a wasteful number, since it uses less digits than its factorization.

548082712113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 182694237374.

The product of its (nonzero) digits is 107520, while the sum is 42.

Adding to 548082712113 its reverse (311217280845), we get a palindrome (859299992958).

The spelling of 548082712113 in words is "five hundred forty-eight billion, eighty-two million, seven hundred twelve thousand, one hundred thirteen".

Divisors: 1 3 182694237371 548082712113