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5482725380131 = 6149638915537
BaseRepresentation
bin100111111001000101111…
…1001100001000000100011
3201102010212120002020002211
41033302023321201000203
51204312110144131011
615354421304422551
71104054021535336
oct117621371410043
921363776066084
105482725380131
1118242355a740a
12746709777a57
1330a03236907c
1414d51864261d
15979419d3b21
hex4fc8be61023

5482725380131 has 4 divisors (see below), whose sum is σ = 5482734910632. Its totient is φ = 5482715849632.

The previous prime is 5482725380113. The next prime is 5482725380149. The reversal of 5482725380131 is 1310835272845.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (5482725380113) and next prime (5482725380149).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5482725380131 is a prime.

It is a super-2 number, since 2×54827253801312 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5482725380731) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3842806 + ... + 5072731.

It is an arithmetic number, because the mean of its divisors is an integer number (1370683727658).

Almost surely, 25482725380131 is an apocalyptic number.

5482725380131 is a deficient number, since it is larger than the sum of its proper divisors (9530501).

5482725380131 is an equidigital number, since it uses as much as digits as its factorization.

5482725380131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9530500.

The product of its (nonzero) digits is 1612800, while the sum is 49.

The spelling of 5482725380131 in words is "five trillion, four hundred eighty-two billion, seven hundred twenty-five million, three hundred eighty thousand, one hundred thirty-one".

Divisors: 1 614963 8915537 5482725380131