Base | Representation |
---|---|
bin | 100111111010010001010… |
… | …1010111011110110110011 |
3 | 201102101101211212001010002 |
4 | 1033310202222323312303 |
5 | 1204332300224330210 |
6 | 15355520305300215 |
7 | 1104203505335120 |
oct | 117644252736663 |
9 | 21371354761102 |
10 | 5485254917555 |
11 | 1825313445306 |
12 | 7470b493466b |
13 | 30a34643aa8a |
14 | 14d6b8581747 |
15 | 97a3dae64a5 |
hex | 4fd22abbdb3 |
5485254917555 has 16 divisors (see below), whose sum is σ = 7782036534720. Its totient is φ = 3631617048192.
The previous prime is 5485254917501. The next prime is 5485254917717. The reversal of 5485254917555 is 5557194525845.
It is not a de Polignac number, because 5485254917555 - 26 = 5485254917491 is a prime.
It is a super-2 number, since 2×54852549175552 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5485254917491 and 5485254917500.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2702095004 + ... + 2702097033.
It is an arithmetic number, because the mean of its divisors is an integer number (486377283420).
Almost surely, 25485254917555 is an apocalyptic number.
5485254917555 is a deficient number, since it is larger than the sum of its proper divisors (2296781617165).
5485254917555 is a wasteful number, since it uses less digits than its factorization.
5485254917555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5404192078.
The product of its digits is 252000000, while the sum is 65.
The spelling of 5485254917555 in words is "five trillion, four hundred eighty-five billion, two hundred fifty-four million, nine hundred seventeen thousand, five hundred fifty-five".
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