Base | Representation |
---|---|
bin | 110011001000110111… |
… | …110000001100000011 |
3 | 12020201202020001022020 |
4 | 303020313300030003 |
5 | 1344423333303201 |
6 | 41120344412523 |
7 | 3652466313642 |
oct | 631067601403 |
9 | 166652201266 |
10 | 54909666051 |
11 | 213180908a9 |
12 | a785177143 |
13 | 5240c90676 |
14 | 292c7d9359 |
15 | 1665905a36 |
hex | cc8df0303 |
54909666051 has 4 divisors (see below), whose sum is σ = 73212888072. Its totient is φ = 36606444032.
The previous prime is 54909666047. The next prime is 54909666079. The reversal of 54909666051 is 15066690945.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 54909666051 - 22 = 54909666047 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 54909665985 and 54909666003.
It is not an unprimeable number, because it can be changed into a prime (54909666041) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9151611006 + ... + 9151611011.
It is an arithmetic number, because the mean of its divisors is an integer number (18303222018).
Almost surely, 254909666051 is an apocalyptic number.
54909666051 is a deficient number, since it is larger than the sum of its proper divisors (18303222021).
54909666051 is a wasteful number, since it uses less digits than its factorization.
54909666051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18303222020.
The product of its (nonzero) digits is 1749600, while the sum is 51.
The spelling of 54909666051 in words is "fifty-four billion, nine hundred nine million, six hundred sixty-six thousand, fifty-one".
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