549719411 has 4 divisors (see below), whose sum is σ = 553011312. Its totient is φ = 546427512.

The previous prime is 549719407. The next prime is 549719441. The reversal of 549719411 is 114917945.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 114917945 = 5 ⋅22983589.

It is a cyclic number.

It is not a de Polignac number, because 549719411 - 2² = 549719407 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (549719441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1645700 + ... + 1646033.

It is an arithmetic number, because the mean of its divisors is an integer number (138252828).

Almost surely, 2^549719411 is an apocalyptic number.

549719411 is a deficient number, since it is larger than the sum of its proper divisors (3291901).

549719411 is a wasteful number, since it uses less digits than its factorization.

549719411 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3291900.

The product of its digits is 45360, while the sum is 41.

The square root of 549719411 is about 23446.0958583727. The cubic root of 549719411 is about 819.1819180908.

The spelling of 549719411 in words is "five hundred forty-nine million, seven hundred nineteen thousand, four hundred eleven".