Base | Representation |
---|---|
bin | 110011001110010000… |
… | …010110011000100011 |
3 | 12020222001012111020100 |
4 | 303032100112120203 |
5 | 1400120000000120 |
6 | 41133332513443 |
7 | 3654644200221 |
oct | 631620263043 |
9 | 166861174210 |
10 | 55000000035 |
11 | 21364080092 |
12 | a7ab47b883 |
13 | 52568cb626 |
14 | 293a7d1b11 |
15 | 166d7eb490 |
hex | cce416623 |
55000000035 has 12 divisors (see below), whose sum is σ = 95333333472. Its totient is φ = 29333333328.
The previous prime is 55000000021. The next prime is 55000000039. The reversal of 55000000035 is 53000000055.
It is not a de Polignac number, because 55000000035 - 220 = 54998951459 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 54999999954 and 55000000017.
It is not an unprimeable number, because it can be changed into a prime (55000000039) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 611111067 + ... + 611111156.
It is an arithmetic number, because the mean of its divisors is an integer number (7944444456).
Almost surely, 255000000035 is an apocalyptic number.
55000000035 is a deficient number, since it is larger than the sum of its proper divisors (40333333437).
55000000035 is a wasteful number, since it uses less digits than its factorization.
55000000035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1222222234 (or 1222222231 counting only the distinct ones).
The product of its (nonzero) digits is 375, while the sum is 18.
The spelling of 55000000035 in words is "fifty-five billion, thirty-five", and thus it is an aban number and an uban number.
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