Base | Representation |
---|---|
bin | 110011001110010001… |
… | …101001011001010011 |
3 | 12020222001211202122112 |
4 | 303032101221121103 |
5 | 1400120041340201 |
6 | 41133344055535 |
7 | 3654650114426 |
oct | 631621513123 |
9 | 166861752575 |
10 | 55000340051 |
11 | 21364292598 |
12 | a7ab6045ab |
13 | 52569ba317 |
14 | 293a87d9bd |
15 | 166d8670bb |
hex | cce469653 |
55000340051 has 8 divisors (see below), whose sum is σ = 55454360400. Its totient is φ = 54547451872.
The previous prime is 55000340029. The next prime is 55000340077. The reversal of 55000340051 is 15004300055.
55000340051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 55000340051 - 214 = 55000323667 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 55000339999 and 55000340026.
It is not an unprimeable number, because it can be changed into a prime (55000340011) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 185345 + ... + 379938.
It is an arithmetic number, because the mean of its divisors is an integer number (6931795050).
Almost surely, 255000340051 is an apocalyptic number.
55000340051 is a deficient number, since it is larger than the sum of its proper divisors (454020349).
55000340051 is a wasteful number, since it uses less digits than its factorization.
55000340051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 566085.
The product of its (nonzero) digits is 1500, while the sum is 23.
The spelling of 55000340051 in words is "fifty-five billion, three hundred forty thousand, fifty-one".
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