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550010131 = 1150000921
BaseRepresentation
bin100000110010000…
…111110100010011
31102022221102001121
4200302013310103
52111300311011
6130324343111
716426003036
oct4062076423
91368842047
10550010131
11262514830
12134244a97
1389c44ca8
145309301d
1533445e71
hex20c87d13

550010131 has 4 divisors (see below), whose sum is σ = 600011064. Its totient is φ = 500009200.

The previous prime is 550010117. The next prime is 550010137. The reversal of 550010131 is 131010055.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 550010131 - 213 = 550001939 is a prime.

It is a super-2 number, since 2×5500101312 = 605022288405274322, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (550010137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25000450 + ... + 25000471.

It is an arithmetic number, because the mean of its divisors is an integer number (150002766).

Almost surely, 2550010131 is an apocalyptic number.

550010131 is a deficient number, since it is larger than the sum of its proper divisors (50000933).

550010131 is a wasteful number, since it uses less digits than its factorization.

550010131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 50000932.

The product of its (nonzero) digits is 75, while the sum is 16.

The square root of 550010131 is about 23452.2947917682. The cubic root of 550010131 is about 819.3263012024.

Adding to 550010131 its reverse (131010055), we get a palindrome (681020186).

The spelling of 550010131 in words is "five hundred fifty million, ten thousand, one hundred thirty-one".

Divisors: 1 11 50000921 550010131