Base | Representation |
---|---|
bin | 110011001110010100… |
… | …101010011010010011 |
3 | 12020222010022221010201 |
4 | 303032110222122103 |
5 | 1400120242140033 |
6 | 41133413040031 |
7 | 3654656616364 |
oct | 631624523223 |
9 | 166863287121 |
10 | 55001130643 |
11 | 21364782578 |
12 | a7ab926017 |
13 | 5256c06124 |
14 | 293aa07b6b |
15 | 166d97147d |
hex | cce52a693 |
55001130643 has 4 divisors (see below), whose sum is σ = 55001602440. Its totient is φ = 55000658848.
The previous prime is 55001130637. The next prime is 55001130689. The reversal of 55001130643 is 34603110055.
55001130643 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 34603110055 = 5 ⋅6920622011.
It is a cyclic number.
It is not a de Polignac number, because 55001130643 - 225 = 54967576211 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (55001130043) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 79803 + ... + 341131.
It is an arithmetic number, because the mean of its divisors is an integer number (13750400610).
Almost surely, 255001130643 is an apocalyptic number.
55001130643 is a deficient number, since it is larger than the sum of its proper divisors (471797).
55001130643 is a wasteful number, since it uses less digits than its factorization.
55001130643 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 471796.
The product of its (nonzero) digits is 5400, while the sum is 28.
Adding to 55001130643 its reverse (34603110055), we get a palindrome (89604240698).
The spelling of 55001130643 in words is "fifty-five billion, one million, one hundred thirty thousand, six hundred forty-three".
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