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55010012113363 = 95848757392549
BaseRepresentation
bin11001000001000000001000…
…01110110010100111010011
321012202220110022211110002111
430200200010032302213103
524202241001100111423
6312555130052130151
714405225244636166
oct1440400416624723
9235686408743074
1055010012113363
11165896848035aa
126205385906957
132490563b56178
14d826da987add
15655e0b33360d
hex3208043b29d3

55010012113363 has 4 divisors (see below), whose sum is σ = 55010070464400. Its totient is φ = 55009953762328.

The previous prime is 55010012113319. The next prime is 55010012113403. The reversal of 55010012113363 is 36331121001055.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 55010012113363 - 29 = 55010012112851 is a prime.

It is a super-2 number, since 2×550100121133632 (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (55010012153363) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27737788 + ... + 29654761.

It is an arithmetic number, because the mean of its divisors is an integer number (13752517616100).

Almost surely, 255010012113363 is an apocalyptic number.

55010012113363 is a deficient number, since it is larger than the sum of its proper divisors (58351037).

55010012113363 is an equidigital number, since it uses as much as digits as its factorization.

55010012113363 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 58351036.

The product of its (nonzero) digits is 8100, while the sum is 31.

The spelling of 55010012113363 in words is "fifty-five trillion, ten billion, twelve million, one hundred thirteen thousand, three hundred sixty-three".

Divisors: 1 958487 57392549 55010012113363