Base | Representation |
---|---|
bin | 11001000001000000001000… |
… | …01110110010100111010011 |
3 | 21012202220110022211110002111 |
4 | 30200200010032302213103 |
5 | 24202241001100111423 |
6 | 312555130052130151 |
7 | 14405225244636166 |
oct | 1440400416624723 |
9 | 235686408743074 |
10 | 55010012113363 |
11 | 165896848035aa |
12 | 6205385906957 |
13 | 2490563b56178 |
14 | d826da987add |
15 | 655e0b33360d |
hex | 3208043b29d3 |
55010012113363 has 4 divisors (see below), whose sum is σ = 55010070464400. Its totient is φ = 55009953762328.
The previous prime is 55010012113319. The next prime is 55010012113403. The reversal of 55010012113363 is 36331121001055.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 55010012113363 - 29 = 55010012112851 is a prime.
It is a super-2 number, since 2×550100121133632 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (55010012153363) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27737788 + ... + 29654761.
It is an arithmetic number, because the mean of its divisors is an integer number (13752517616100).
Almost surely, 255010012113363 is an apocalyptic number.
55010012113363 is a deficient number, since it is larger than the sum of its proper divisors (58351037).
55010012113363 is an equidigital number, since it uses as much as digits as its factorization.
55010012113363 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 58351036.
The product of its (nonzero) digits is 8100, while the sum is 31.
The spelling of 55010012113363 in words is "fifty-five trillion, ten billion, twelve million, one hundred thirteen thousand, three hundred sixty-three".
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