Base | Representation |
---|---|
bin | 100000110010101… |
… | …111101011111001 |
3 | 1102100020201001211 |
4 | 200302233223321 |
5 | 2111321022213 |
6 | 130332043121 |
7 | 16430253115 |
oct | 4062575371 |
9 | 1370221054 |
10 | 550173433 |
11 | 262616497 |
12 | 1343034a1 |
13 | 89ca1414 |
14 | 530d6745 |
15 | 3347953d |
hex | 20cafaf9 |
550173433 has 4 divisors (see below), whose sum is σ = 562968208. Its totient is φ = 537378660.
The previous prime is 550173419. The next prime is 550173487. The reversal of 550173433 is 334371055.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 550173433 - 25 = 550173401 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 550173395 and 550173404.
It is not an unprimeable number, because it can be changed into a prime (550173733) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6397323 + ... + 6397408.
It is an arithmetic number, because the mean of its divisors is an integer number (140742052).
Almost surely, 2550173433 is an apocalyptic number.
It is an amenable number.
550173433 is a deficient number, since it is larger than the sum of its proper divisors (12794775).
550173433 is a wasteful number, since it uses less digits than its factorization.
550173433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12794774.
The product of its (nonzero) digits is 18900, while the sum is 31.
The square root of 550173433 is about 23455.7761116532. The cubic root of 550173433 is about 819.4073811537.
The spelling of 550173433 in words is "five hundred fifty million, one hundred seventy-three thousand, four hundred thirty-three".
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