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550255310401 = 1035342284567
BaseRepresentation
bin10000000000111011100…
…01011011011001000001
31221121022020102222220011
420000131301123121001
533003410324413101
61100441144544521
754516560652316
oct10003561333101
91847266388804
10550255310401
111a23a8860a85
128a787482141
133cb72a6c334
141c8bd812d0d
15e4a7b0a751
hex801dc5b641

550255310401 has 4 divisors (see below), whose sum is σ = 555597595072. Its totient is φ = 544913025732.

The previous prime is 550255310357. The next prime is 550255310417. The reversal of 550255310401 is 104013552055.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 550255310401 - 221 = 550253213249 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (550255310441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2671142181 + ... + 2671142386.

It is an arithmetic number, because the mean of its divisors is an integer number (138899398768).

Almost surely, 2550255310401 is an apocalyptic number.

It is an amenable number.

550255310401 is a deficient number, since it is larger than the sum of its proper divisors (5342284671).

550255310401 is a wasteful number, since it uses less digits than its factorization.

550255310401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5342284670.

The product of its (nonzero) digits is 15000, while the sum is 31.

Adding to 550255310401 its reverse (104013552055), we get a palindrome (654268862456).

The spelling of 550255310401 in words is "five hundred fifty billion, two hundred fifty-five million, three hundred ten thousand, four hundred one".

Divisors: 1 103 5342284567 550255310401