Base | Representation |
---|---|
bin | 10000000001000001000… |
… | …01010000000100000001 |
3 | 1221121102110011122210011 |
4 | 20000200201100010001 |
5 | 33004004124320340 |
6 | 1100445512504521 |
7 | 54520660506253 |
oct | 10004041200401 |
9 | 1847373148704 |
10 | 550301401345 |
11 | 1a2421881873 |
12 | 8a79a9ab141 |
13 | 3cb7c489397 |
14 | 1c8c59adcd3 |
15 | e4abbb20ea |
hex | 8020850101 |
550301401345 has 4 divisors (see below), whose sum is σ = 660361681620. Its totient is φ = 440241121072.
The previous prime is 550301401343. The next prime is 550301401367. The reversal of 550301401345 is 543104103055.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 257356333809 + 292945067536 = 507303^2 + 541244^2 .
It is a cyclic number.
It is not a de Polignac number, because 550301401345 - 21 = 550301401343 is a prime.
It is not an unprimeable number, because it can be changed into a prime (550301401343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (7) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55030140130 + ... + 55030140139.
It is an arithmetic number, because the mean of its divisors is an integer number (165090420405).
Almost surely, 2550301401345 is an apocalyptic number.
It is an amenable number.
550301401345 is a deficient number, since it is larger than the sum of its proper divisors (110060280275).
550301401345 is a wasteful number, since it uses less digits than its factorization.
550301401345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 110060280274.
The product of its (nonzero) digits is 18000, while the sum is 31.
The spelling of 550301401345 in words is "five hundred fifty billion, three hundred one million, four hundred one thousand, three hundred forty-five".
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