Search a number
-
+
550311105 = 35291265083
BaseRepresentation
bin100000110011010…
…001010011000001
31102100111200220210
4200303101103001
52111334423410
6130335024333
716431365361
oct4063212301
91370450823
10550311105
112626aa973
1213436b0a9
138a01bc96
14531309a1
15334a5220
hex20cd14c1

550311105 has 16 divisors (see below), whose sum is σ = 910860480. Its totient is φ = 283378368.

The previous prime is 550311103. The next prime is 550311107. The reversal of 550311105 is 501113055.

It is an interprime number because it is at equal distance from previous prime (550311103) and next prime (550311107).

It is not a de Polignac number, because 550311105 - 21 = 550311103 is a prime.

It is not an unprimeable number, because it can be changed into a prime (550311103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 632107 + ... + 632976.

It is an arithmetic number, because the mean of its divisors is an integer number (56928780).

Almost surely, 2550311105 is an apocalyptic number.

It is an amenable number.

550311105 is a deficient number, since it is larger than the sum of its proper divisors (360549375).

550311105 is a wasteful number, since it uses less digits than its factorization.

550311105 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1265120.

The product of its (nonzero) digits is 375, while the sum is 21.

The square root of 550311105 is about 23458.7106423179. The cubic root of 550311105 is about 819.4757232667.

It can be divided in two parts, 550 and 311105, that added together give a triangular number (311655 = T789).

The spelling of 550311105 in words is "five hundred fifty million, three hundred eleven thousand, one hundred five".

Divisors: 1 3 5 15 29 87 145 435 1265083 3795249 6325415 18976245 36687407 110062221 183437035 550311105