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550344156433 = 797121978287
BaseRepresentation
bin10000000001000110001…
…00010110010100010001
31221121112102121211201221
420000203010112110101
533004101101001213
61100454041125041
754522020100541
oct10004304262421
91847472554657
10550344156433
111a2443a24355
128a7b1189781
133cb882a8c56
141c8cb53d321
15e4b080a38d
hex8023116511

550344156433 has 8 divisors (see below), whose sum is σ = 557389370880. Its totient is φ = 543300912960.

The previous prime is 550344156413. The next prime is 550344156443. The reversal of 550344156433 is 334651443055.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-550344156433 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 550344156433.

It is not an unprimeable number, because it can be changed into a prime (550344156403) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 73416 + ... + 1051702.

It is an arithmetic number, because the mean of its divisors is an integer number (69673671360).

Almost surely, 2550344156433 is an apocalyptic number.

It is an amenable number.

550344156433 is a deficient number, since it is larger than the sum of its proper divisors (7045214447).

550344156433 is an equidigital number, since it uses as much as digits as its factorization.

550344156433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 985487.

The product of its (nonzero) digits is 1296000, while the sum is 43.

Adding to 550344156433 its reverse (334651443055), we get a palindrome (884995599488).

The spelling of 550344156433 in words is "five hundred fifty billion, three hundred forty-four million, one hundred fifty-six thousand, four hundred thirty-three".

Divisors: 1 79 7121 562559 978287 77284673 6966381727 550344156433