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55038315137 = 134233716549
BaseRepresentation
bin110011010000100010…
…100000101010000001
312021001201022002200012
4303100202200222001
51400204302041022
641141222034305
73655620650111
oct632042405201
9167051262605
1055038315137
112138376a863
12a800278995
1352618252a0
142941927041
151671d68de2
hexcd08a0a81

55038315137 has 4 divisors (see below), whose sum is σ = 59272031700. Its totient is φ = 50804598576.

The previous prime is 55038315097. The next prime is 55038315161. The reversal of 55038315137 is 73151383055.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 27752561281 + 27285753856 = 166591^2 + 165184^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-55038315137 is a prime.

It is a super-2 number, since 2×550383151372 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 55038315094 and 55038315103.

It is not an unprimeable number, because it can be changed into a prime (55038311137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2116858262 + ... + 2116858287.

It is an arithmetic number, because the mean of its divisors is an integer number (14818007925).

Almost surely, 255038315137 is an apocalyptic number.

It is an amenable number.

55038315137 is a deficient number, since it is larger than the sum of its proper divisors (4233716563).

55038315137 is a wasteful number, since it uses less digits than its factorization.

55038315137 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4233716562.

The product of its (nonzero) digits is 189000, while the sum is 41.

The spelling of 55038315137 in words is "fifty-five billion, thirty-eight million, three hundred fifteen thousand, one hundred thirty-seven".

Divisors: 1 13 4233716549 55038315137