Base | Representation |
---|---|
bin | 110011010000110110… |
… | …010010101000111001 |
3 | 12021002002001112210102 |
4 | 303100312102220321 |
5 | 1400212114004401 |
6 | 41141525125145 |
7 | 3656013015065 |
oct | 632066225071 |
9 | 167062045712 |
10 | 55043500601 |
11 | 21386691771 |
12 | a801b597b5 |
13 | 526291c5cb |
14 | 29424b6aa5 |
15 | 167254056b |
hex | cd0d92a39 |
55043500601 has 4 divisors (see below), whose sum is σ = 55044539472. Its totient is φ = 55042461732.
The previous prime is 55043500579. The next prime is 55043500613. The reversal of 55043500601 is 10600534055.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 55043500601 - 222 = 55039306297 is a prime.
It is a super-2 number, since 2×550435006012 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (55043500301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 435431 + ... + 547436.
It is an arithmetic number, because the mean of its divisors is an integer number (13761134868).
Almost surely, 255043500601 is an apocalyptic number.
It is an amenable number.
55043500601 is a deficient number, since it is larger than the sum of its proper divisors (1038871).
55043500601 is an equidigital number, since it uses as much as digits as its factorization.
55043500601 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1038870.
The product of its (nonzero) digits is 9000, while the sum is 29.
The spelling of 55043500601 in words is "fifty-five billion, forty-three million, five hundred thousand, six hundred one".
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