Base | Representation |
---|---|
bin | 11001000001111111101100… |
… | …00101101110111000100011 |
3 | 21012220011112101022011200120 |
4 | 30200333312011232320203 |
5 | 24203320341424034011 |
6 | 313022532031251323 |
7 | 14410543653153222 |
oct | 1440776605567043 |
9 | 235804471264616 |
10 | 55044134596131 |
11 | 165a20a4a8898a |
12 | 620bb09379b43 |
13 | 2493841325985 |
14 | d8421670acb9 |
15 | 656c56d28a06 |
hex | 320ff616ee23 |
55044134596131 has 4 divisors (see below), whose sum is σ = 73392179461512. Its totient is φ = 36696089730752.
The previous prime is 55044134596123. The next prime is 55044134596177. The reversal of 55044134596131 is 13169543144055.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 55044134596131 - 23 = 55044134596123 is a prime.
It is a super-2 number, since 2×550441345961312 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (55044134592131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9174022432686 + ... + 9174022432691.
It is an arithmetic number, because the mean of its divisors is an integer number (18348044865378).
Almost surely, 255044134596131 is an apocalyptic number.
55044134596131 is a deficient number, since it is larger than the sum of its proper divisors (18348044865381).
55044134596131 is a wasteful number, since it uses less digits than its factorization.
55044134596131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18348044865380.
The product of its (nonzero) digits is 3888000, while the sum is 51.
The spelling of 55044134596131 in words is "fifty-five trillion, forty-four billion, one hundred thirty-four million, five hundred ninety-six thousand, one hundred thirty-one".
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