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55045263406153 = 311775653658263
BaseRepresentation
bin11001000010000001110010…
…10111110011010001001001
321012220021110001100122221011
430201000321113303101021
524203330144412444103
6313023240033443521
714410613640660436
oct1441007127632111
9235807401318834
1055045263406153
11165a2624190629
1262101834105a1
132493991152ab7
14d842c25c8b8d
15656cc0ea0d6d
hex3210395f3449

55045263406153 has 4 divisors (see below), whose sum is σ = 56820917064448. Its totient is φ = 53269609747860.

The previous prime is 55045263406139. The next prime is 55045263406157. The reversal of 55045263406153 is 35160436254055.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 55045263406153 - 217 = 55045263275081 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 55045263406097 and 55045263406106.

It is not an unprimeable number, because it can be changed into a prime (55045263406157) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 887826829101 + ... + 887826829162.

It is an arithmetic number, because the mean of its divisors is an integer number (14205229266112).

Almost surely, 255045263406153 is an apocalyptic number.

It is an amenable number.

55045263406153 is a deficient number, since it is larger than the sum of its proper divisors (1775653658295).

55045263406153 is a wasteful number, since it uses less digits than its factorization.

55045263406153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1775653658294.

The product of its (nonzero) digits is 6480000, while the sum is 49.

The spelling of 55045263406153 in words is "fifty-five trillion, forty-five billion, two hundred sixty-three million, four hundred six thousand, one hundred fifty-three".

Divisors: 1 31 1775653658263 55045263406153