55054013140403 has 8 divisors (see below), whose sum is σ = 55404989224080. Its totient is φ = 54703041026400.

The previous prime is 55054013140381. The next prime is 55054013140597. The reversal of 55054013140403 is 30404131045055.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 55054013140403 - 2³⁴ = 55036833271219 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (55054013140103) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 29885693 + ... + 31674321.

It is an arithmetic number, because the mean of its divisors is an integer number (6925623653010).

Almost surely, 2^{55054013140403} is an apocalyptic number.

55054013140403 is a deficient number, since it is larger than the sum of its proper divisors (350976083677).

55054013140403 is a wasteful number, since it uses less digits than its factorization.

55054013140403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1984837.

The product of its (nonzero) digits is 72000, while the sum is 35.

Adding to 55054013140403 its reverse (30404131045055), we get a palindrome (85458144185458).

The spelling of 55054013140403 in words is "fifty-five trillion, fifty-four billion, thirteen million, one hundred forty thousand, four hundred three".