Base | Representation |
---|---|
bin | 10000000001011101101… |
… | …00011101111101000011 |
3 | 1221122001011121210022101 |
4 | 20000232310131331003 |
5 | 33010002034220003 |
6 | 1100525403051231 |
7 | 54526633002463 |
oct | 10005664357503 |
9 | 1848034553271 |
10 | 550541320003 |
11 | 1a253524a254 |
12 | 8a847210b17 |
13 | 3cbba0ac19c |
14 | 1c9097c3ba3 |
15 | e4c2ca411d |
hex | 802ed1df43 |
550541320003 has 4 divisors (see below), whose sum is σ = 551282291568. Its totient is φ = 549800348440.
The previous prime is 550541319971. The next prime is 550541320033. The reversal of 550541320003 is 300023145055.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 550541320003 - 25 = 550541319971 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (550541320033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 370484668 + ... + 370486153.
It is an arithmetic number, because the mean of its divisors is an integer number (137820572892).
Almost surely, 2550541320003 is an apocalyptic number.
550541320003 is a deficient number, since it is larger than the sum of its proper divisors (740971565).
550541320003 is an equidigital number, since it uses as much as digits as its factorization.
550541320003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 740971564.
The product of its (nonzero) digits is 9000, while the sum is 28.
Adding to 550541320003 its reverse (300023145055), we get a palindrome (850564465058).
The spelling of 550541320003 in words is "five hundred fifty billion, five hundred forty-one million, three hundred twenty thousand, three".
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