Base | Representation |
---|---|
bin | 110011010001100100… |
… | …010001110110100001 |
3 | 12021002220202000200201 |
4 | 303101210101312201 |
5 | 1400223210243001 |
6 | 41143035345201 |
7 | 3656220335035 |
oct | 632144216641 |
9 | 167086660621 |
10 | 55055556001 |
11 | 21392476106 |
12 | a805bb2201 |
13 | 5265280894 |
14 | 2943d341c5 |
15 | 1673622501 |
hex | cd1911da1 |
55055556001 has 4 divisors (see below), whose sum is σ = 55168606912. Its totient is φ = 54942505092.
The previous prime is 55055555993. The next prime is 55055556011. The reversal of 55055556001 is 10065555055.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 55055556001 - 23 = 55055555993 is a prime.
It is a super-2 number, since 2×550555560012 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (55055556011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56524725 + ... + 56525698.
It is an arithmetic number, because the mean of its divisors is an integer number (13792151728).
Almost surely, 255055556001 is an apocalyptic number.
It is an amenable number.
55055556001 is a deficient number, since it is larger than the sum of its proper divisors (113050911).
55055556001 is a wasteful number, since it uses less digits than its factorization.
55055556001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 113050910.
The product of its (nonzero) digits is 93750, while the sum is 37.
The spelling of 55055556001 in words is "fifty-five billion, fifty-five million, five hundred fifty-six thousand, one".
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