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55061011001011 = 291898655551759
BaseRepresentation
bin11001000010011111001000…
…00000000110111010110011
321012221210002112020100222011
430201033210000012322303
524204104422304013021
6313034402415223351
714412012116220631
oct1441174400067263
9235853075210864
1055061011001011
11165a92752aa734
126213239217b57
132495300833972
14d84d77c16351
156573e3739de1
hex3213e4006eb3

55061011001011 has 4 divisors (see below), whose sum is σ = 56959666552800. Its totient is φ = 53162355449224.

The previous prime is 55061011000993. The next prime is 55061011001021. The reversal of 55061011001011 is 11010011016055.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-55061011001011 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (55061011001021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 949327775851 + ... + 949327775908.

It is an arithmetic number, because the mean of its divisors is an integer number (14239916638200).

Almost surely, 255061011001011 is an apocalyptic number.

55061011001011 is a deficient number, since it is larger than the sum of its proper divisors (1898655551789).

55061011001011 is a wasteful number, since it uses less digits than its factorization.

55061011001011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1898655551788.

The product of its (nonzero) digits is 150, while the sum is 22.

Adding to 55061011001011 its reverse (11010011016055), we get a palindrome (66071022017066).

The spelling of 55061011001011 in words is "fifty-five trillion, sixty-one billion, eleven million, one thousand, eleven".

Divisors: 1 29 1898655551759 55061011001011