Base | Representation |
---|---|
bin | 11001000010110010110010… |
… | …01101100101100010010001 |
3 | 21012222210100012222011100021 |
4 | 30201121121031211202101 |
5 | 24204243032223400103 |
6 | 313043310115423441 |
7 | 14412534531160360 |
oct | 1441313115454221 |
9 | 235883305864307 |
10 | 55071567403153 |
11 | 166027a20a4924 |
12 | 62152a45b4b81 |
13 | 24962c3893672 |
14 | d85699c137d7 |
15 | 6578103a2bbd |
hex | 321659365891 |
55071567403153 has 4 divisors (see below), whose sum is σ = 62938934175040. Its totient is φ = 47204200631268.
The previous prime is 55071567403129. The next prime is 55071567403201. The reversal of 55071567403153 is 35130476517055.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 55071567403153 - 25 = 55071567403121 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 55071567403153.
It is not an unprimeable number, because it can be changed into a prime (55071567403123) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3933683385933 + ... + 3933683385946.
It is an arithmetic number, because the mean of its divisors is an integer number (15734733543760).
Almost surely, 255071567403153 is an apocalyptic number.
It is an amenable number.
55071567403153 is a deficient number, since it is larger than the sum of its proper divisors (7867366771887).
55071567403153 is an equidigital number, since it uses as much as digits as its factorization.
55071567403153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7867366771886.
The product of its (nonzero) digits is 6615000, while the sum is 52.
The spelling of 55071567403153 in words is "fifty-five trillion, seventy-one billion, five hundred sixty-seven million, four hundred three thousand, one hundred fifty-three".
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