Base | Representation |
---|---|
bin | 11001000010110101110000… |
… | …11111110000001010100011 |
3 | 21012222221110122000100001122 |
4 | 30201122320133300022203 |
5 | 24204304320444011203 |
6 | 313044132503122455 |
7 | 14412622252060046 |
oct | 1441327037601243 |
9 | 235887418010048 |
10 | 55073166000803 |
11 | 166034424a8a05 |
12 | 621566ba4342b |
13 | 24964b9b28032 |
14 | d857ac260c5d |
15 | 6578a58c6538 |
hex | 3216b87f02a3 |
55073166000803 has 4 divisors (see below), whose sum is σ = 55073197385880. Its totient is φ = 55073134615728.
The previous prime is 55073166000733. The next prime is 55073166000829. The reversal of 55073166000803 is 30800066137055.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 55073166000803 - 28 = 55073166000547 is a prime.
It is a super-2 number, since 2×550731660008032 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (55073166000863) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12894050 + ... + 16625367.
It is an arithmetic number, because the mean of its divisors is an integer number (13768299346470).
Almost surely, 255073166000803 is an apocalyptic number.
55073166000803 is a deficient number, since it is larger than the sum of its proper divisors (31385077).
55073166000803 is a wasteful number, since it uses less digits than its factorization.
55073166000803 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31385076.
The product of its (nonzero) digits is 453600, while the sum is 44.
The spelling of 55073166000803 in words is "fifty-five trillion, seventy-three billion, one hundred sixty-six million, eight hundred three", and thus it is an aban number.
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