Base | Representation |
---|---|
bin | 111110101001010110101011… |
… | …1011100001100001000101011 |
3 | 2200021002001100220210101110012 |
4 | 1331102231113130030020223 |
5 | 1034211230420341221120 |
6 | 5231544543122442135 |
7 | 224032301320463051 |
oct | 17522552734141053 |
9 | 2607061326711405 |
10 | 551041476117035 |
11 | 14a640417712422 |
12 | 5197764350334b |
13 | 1a861cb01b4387 |
14 | 9a1079a7221d1 |
15 | 43a8cc01891c5 |
hex | 1f52b5770c22b |
551041476117035 has 4 divisors (see below), whose sum is σ = 661249771340448. Its totient is φ = 440833180893624.
The previous prime is 551041476117017. The next prime is 551041476117037. The reversal of 551041476117035 is 530711674140155.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 551041476117035 - 28 = 551041476116779 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (551041476117037) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55104147611699 + ... + 55104147611708.
It is an arithmetic number, because the mean of its divisors is an integer number (165312442835112).
Almost surely, 2551041476117035 is an apocalyptic number.
551041476117035 is a deficient number, since it is larger than the sum of its proper divisors (110208295223413).
551041476117035 is a wasteful number, since it uses less digits than its factorization.
551041476117035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 110208295223412.
The product of its (nonzero) digits is 1764000, while the sum is 50.
The spelling of 551041476117035 in words is "five hundred fifty-one trillion, forty-one billion, four hundred seventy-six million, one hundred seventeen thousand, thirty-five".
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