Base | Representation |
---|---|
bin | 110011010100100010… |
… | …111110000010011001 |
3 | 12021020101210200210212 |
4 | 303110202332002121 |
5 | 1400324004404340 |
6 | 41152023020505 |
7 | 3660365253455 |
oct | 632442760231 |
9 | 167211720725 |
10 | 55105544345 |
11 | 21408709095 |
12 | a81a89a735 |
13 | 5272733897 |
14 | 294a827665 |
15 | 1677be8a65 |
hex | cd48be099 |
55105544345 has 4 divisors (see below), whose sum is σ = 66126653220. Its totient is φ = 44084435472.
The previous prime is 55105544339. The next prime is 55105544357. The reversal of 55105544345 is 54344550155.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 9227331481 + 45878212864 = 96059^2 + 214192^2 .
It is a cyclic number.
It is not a de Polignac number, because 55105544345 - 26 = 55105544281 is a prime.
It is a super-2 number, since 2×551055443452 (a number of 22 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5510554430 + ... + 5510554439.
It is an arithmetic number, because the mean of its divisors is an integer number (16531663305).
Almost surely, 255105544345 is an apocalyptic number.
It is an amenable number.
55105544345 is a deficient number, since it is larger than the sum of its proper divisors (11021108875).
55105544345 is a wasteful number, since it uses less digits than its factorization.
55105544345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11021108874.
The product of its (nonzero) digits is 600000, while the sum is 41.
The spelling of 55105544345 in words is "fifty-five billion, one hundred five million, five hundred forty-four thousand, three hundred forty-five".
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