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551213453545 = 5110242690709
BaseRepresentation
bin10000000010101101110…
…00011101000011101001
31221200210000100201012021
420001112320131003221
533012341121003140
61101120213144441
754552404022466
oct10012670350351
91850700321167
10551213453545
111a284a696117
128a9b432b121
133cc96412741
141c970b8666d
15e511cbeb4a
hex8056e1d0e9

551213453545 has 4 divisors (see below), whose sum is σ = 661456144260. Its totient is φ = 440970762832.

The previous prime is 551213453519. The next prime is 551213453551. The reversal of 551213453545 is 545354312155.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 545354312155 = 5109070862431.

It can be written as a sum of positive squares in 2 ways, for example, as 222801936361 + 328411517184 = 472019^2 + 573072^2 .

It is a cyclic number.

It is not a de Polignac number, because 551213453545 - 213 = 551213445353 is a prime.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55121345350 + ... + 55121345359.

It is an arithmetic number, because the mean of its divisors is an integer number (165364036065).

Almost surely, 2551213453545 is an apocalyptic number.

It is an amenable number.

551213453545 is a deficient number, since it is larger than the sum of its proper divisors (110242690715).

551213453545 is a wasteful number, since it uses less digits than its factorization.

551213453545 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 110242690714.

The product of its digits is 900000, while the sum is 43.

The spelling of 551213453545 in words is "five hundred fifty-one billion, two hundred thirteen million, four hundred fifty-three thousand, five hundred forty-five".

Divisors: 1 5 110242690709 551213453545