55121432016403 has 8 divisors (see below), whose sum is σ = 55611545260896. Its totient is φ = 54631359350400.

The previous prime is 55121432016379. The next prime is 55121432016451. The reversal of 55121432016403 is 30461023412155.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-55121432016403 is a prime.

It is a super-2 number, since 2×55121432016403² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (55121432019403) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7412508 + ... + 12852553.

It is an arithmetic number, because the mean of its divisors is an integer number (6951443157612).

Almost surely, 2^{55121432016403} is an apocalyptic number.

55121432016403 is a deficient number, since it is larger than the sum of its proper divisors (490113244493).

55121432016403 is a wasteful number, since it uses less digits than its factorization.

55121432016403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20289245.

The product of its (nonzero) digits is 86400, while the sum is 37.

Adding to 55121432016403 its reverse (30461023412155), we get a palindrome (85582455428558).

The spelling of 55121432016403 in words is "fifty-five trillion, one hundred twenty-one billion, four hundred thirty-two million, sixteen thousand, four hundred three".