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55122132113 = 96757003239
BaseRepresentation
bin110011010101100010…
…001111110010010001
312021021120000102221122
4303111202033302101
51400342231211423
641153414332025
73660656251346
oct632542176221
9167246012848
1055122132113
1121417008794
12a82435a015
135275cc0b29
14294cb047cd
1516793c38c8
hexcd588fc91

55122132113 has 4 divisors (see below), whose sum is σ = 55179136320. Its totient is φ = 55065127908.

The previous prime is 55122132011. The next prime is 55122132119. The reversal of 55122132113 is 31123122155.

55122132113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 55122132113 - 214 = 55122115729 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (55122132119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28500653 + ... + 28502586.

It is an arithmetic number, because the mean of its divisors is an integer number (13794784080).

Almost surely, 255122132113 is an apocalyptic number.

It is an amenable number.

55122132113 is a deficient number, since it is larger than the sum of its proper divisors (57004207).

55122132113 is an equidigital number, since it uses as much as digits as its factorization.

55122132113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 57004206.

The product of its digits is 1800, while the sum is 26.

Adding to 55122132113 its reverse (31123122155), we get a palindrome (86245254268).

The spelling of 55122132113 in words is "fifty-five billion, one hundred twenty-two million, one hundred thirty-two thousand, one hundred thirteen".

Divisors: 1 967 57003239 55122132113