551243003134433 has 4 divisors (see below), whose sum is σ = 551243568073920. Its totient is φ = 551242438194948.

The previous prime is 551243003134303. The next prime is 551243003134553. The reversal of 551243003134433 is 334431300342155.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-551243003134433 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (551243003934433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 281003573 + ... + 282958466.

It is an arithmetic number, because the mean of its divisors is an integer number (137810892018480).

Almost surely, 2^{551243003134433} is an apocalyptic number.

It is an amenable number.

551243003134433 is a deficient number, since it is larger than the sum of its proper divisors (564939487).

551243003134433 is an equidigital number, since it uses as much as digits as its factorization.

551243003134433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 564939486.

The product of its (nonzero) digits is 777600, while the sum is 41.

Adding to 551243003134433 its reverse (334431300342155), we get a palindrome (885674303476588).

The spelling of 551243003134433 in words is "five hundred fifty-one trillion, two hundred forty-three billion, three million, one hundred thirty-four thousand, four hundred thirty-three".