Base | Representation |
---|---|
bin | 10000000010110010010… |
… | …00100110010010111011 |
3 | 1221200212122110110122011 |
4 | 20001121020212102323 |
5 | 33012430304140443 |
6 | 1101124043110351 |
7 | 54553343141443 |
oct | 10013110462273 |
9 | 1850778413564 |
10 | 551251240123 |
11 | 1a2869a547a1 |
12 | 8aa04b123b7 |
13 | 3cca11b296c |
14 | 1c975bc1123 |
15 | e515285b9d |
hex | 80592264bb |
551251240123 has 4 divisors (see below), whose sum is σ = 558802627048. Its totient is φ = 543699853200.
The previous prime is 551251240117. The next prime is 551251240147. The reversal of 551251240123 is 321042152155.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 321042152155 = 5 ⋅64208430431.
It is a cyclic number.
It is not a de Polignac number, because 551251240123 - 213 = 551251231931 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (551251240153) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3775693353 + ... + 3775693498.
It is an arithmetic number, because the mean of its divisors is an integer number (139700656762).
Almost surely, 2551251240123 is an apocalyptic number.
551251240123 is a deficient number, since it is larger than the sum of its proper divisors (7551386925).
551251240123 is an equidigital number, since it uses as much as digits as its factorization.
551251240123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7551386924.
The product of its (nonzero) digits is 12000, while the sum is 31.
Adding to 551251240123 its reverse (321042152155), we get a palindrome (872293392278).
The spelling of 551251240123 in words is "five hundred fifty-one billion, two hundred fifty-one million, two hundred forty thousand, one hundred twenty-three".
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