Base | Representation |
---|---|
bin | 10000000010111011111… |
… | …10010010100110111001 |
3 | 1221201002022020001010220 |
4 | 20001131332102212321 |
5 | 33013112100032441 |
6 | 1101140103130253 |
7 | 54555350165463 |
oct | 10013576224671 |
9 | 1851068201126 |
10 | 551332424121 |
11 | 1a2900864506 |
12 | 8aa28143989 |
13 | 3ccb4c68c2b |
14 | 1c9828b5133 |
15 | e51c470466 |
hex | 805df929b9 |
551332424121 has 8 divisors (see below), whose sum is σ = 747160881024. Its totient is φ = 361529458320.
The previous prime is 551332424119. The next prime is 551332424161. The reversal of 551332424121 is 121424233155.
551332424121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 551332424121 - 21 = 551332424119 is a prime.
It is a super-3 number, since 3×5513324241213 (a number of 36 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (551332424101) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1506372561 + ... + 1506372926.
It is an arithmetic number, because the mean of its divisors is an integer number (93395110128).
Almost surely, 2551332424121 is an apocalyptic number.
It is an amenable number.
551332424121 is a deficient number, since it is larger than the sum of its proper divisors (195828456903).
551332424121 is a wasteful number, since it uses less digits than its factorization.
551332424121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3012745551.
The product of its digits is 28800, while the sum is 33.
Adding to 551332424121 its reverse (121424233155), we get a palindrome (672756657276).
The spelling of 551332424121 in words is "five hundred fifty-one billion, three hundred thirty-two million, four hundred twenty-four thousand, one hundred twenty-one".
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