Base | Representation |
---|---|
bin | 11001000100100111101010… |
… | …00010101110010000110011 |
3 | 21020012210021221202120010222 |
4 | 30202103311002232100303 |
5 | 24211310032200440110 |
6 | 313132204124043255 |
7 | 14420215426646222 |
oct | 1442236502562063 |
9 | 236183257676128 |
10 | 55134311343155 |
11 | 1662736a44a6a0 |
12 | 622549539352b |
13 | 249c1b2950295 |
14 | d8872cc96cb9 |
15 | 659283969c55 |
hex | 3224f50ae433 |
55134311343155 has 8 divisors (see below), whose sum is σ = 72175825758384. Its totient is φ = 40097680976800.
The previous prime is 55134311343151. The next prime is 55134311343169.
55134311343155 is nontrivially palindromic in base 10.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 55134311343155 - 22 = 55134311343151 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (55134311343151) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 501221012156 + ... + 501221012265.
It is an arithmetic number, because the mean of its divisors is an integer number (9021978219798).
Almost surely, 255134311343155 is an apocalyptic number.
55134311343155 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
55134311343155 is a deficient number, since it is larger than the sum of its proper divisors (17041514415229).
55134311343155 is a wasteful number, since it uses less digits than its factorization.
55134311343155 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1002442024437.
The product of its digits is 810000, while the sum is 44.
It can be divided in two parts, 5513431 and 1343155, that added together give a palindrome (6856586).
The spelling of 55134311343155 in words is "fifty-five trillion, one hundred thirty-four billion, three hundred eleven million, three hundred forty-three thousand, one hundred fifty-five".
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