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551415131113 = 7117161235469
BaseRepresentation
bin10000000011000101110…
…01110010101111101001
31221201022001211222210211
420001202321302233221
533013244233143423
61101152215541121
754560403164650
oct10014271625751
91851261758724
10551415131113
111a29435144a0
128aa4b98a7a1
133ccc9136492
141c98d884197
15e52485b10d
hex8062e72be9

551415131113 has 8 divisors (see below), whose sum is σ = 687478605120. Its totient is φ = 429674128080.

The previous prime is 551415131083. The next prime is 551415131131. The reversal of 551415131113 is 311131514155.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-551415131113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (551415131713) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3580617658 + ... + 3580617811.

It is an arithmetic number, because the mean of its divisors is an integer number (85934825640).

Almost surely, 2551415131113 is an apocalyptic number.

It is an amenable number.

551415131113 is a deficient number, since it is larger than the sum of its proper divisors (136063474007).

551415131113 is a wasteful number, since it uses less digits than its factorization.

551415131113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7161235487.

The product of its digits is 4500, while the sum is 31.

Adding to 551415131113 its reverse (311131514155), we get a palindrome (862546645268).

The spelling of 551415131113 in words is "five hundred fifty-one billion, four hundred fifteen million, one hundred thirty-one thousand, one hundred thirteen".

Divisors: 1 7 11 77 7161235469 50128648283 78773590159 551415131113