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55143045121 = 280191968059
BaseRepresentation
bin110011010110110010…
…000001100000000001
312021100000100221012111
4303112302001200001
51400413104420441
641155442455321
73661332102253
oct632662014001
9167300327174
1055143045121
11214278a1a6a
12a82b364541
13527a4339a8
1429517c9cd3
15167b155081
hexcd6c81801

55143045121 has 4 divisors (see below), whose sum is σ = 55145041200. Its totient is φ = 55141049044.

The previous prime is 55143045109. The next prime is 55143045131. The reversal of 55143045121 is 12154034155.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 55143045121 - 213 = 55143036929 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (55143045101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 956011 + ... + 1012048.

It is an arithmetic number, because the mean of its divisors is an integer number (13786260300).

Almost surely, 255143045121 is an apocalyptic number.

It is an amenable number.

55143045121 is a deficient number, since it is larger than the sum of its proper divisors (1996079).

55143045121 is a wasteful number, since it uses less digits than its factorization.

55143045121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1996078.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 55143045121 its reverse (12154034155), we get a palindrome (67297079276).

The spelling of 55143045121 in words is "fifty-five billion, one hundred forty-three million, forty-five thousand, one hundred twenty-one".

Divisors: 1 28019 1968059 55143045121