Base | Representation |
---|---|
bin | 110011010110110011… |
… | …000111110010001001 |
3 | 12021100000220120002201 |
4 | 303112303013302021 |
5 | 1400413143124001 |
6 | 41155453000201 |
7 | 3661334411461 |
oct | 632663076211 |
9 | 167300816081 |
10 | 55143333001 |
11 | 21427a79289 |
12 | a82b483061 |
13 | 527a504a33 |
14 | 2951862ba1 |
15 | 167b1b0501 |
hex | cd6cc7c89 |
55143333001 has 4 divisors (see below), whose sum is σ = 55145663104. Its totient is φ = 55141002900.
The previous prime is 55143332971. The next prime is 55143333019. The reversal of 55143333001 is 10033334155.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 55143333001 - 25 = 55143332969 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (55143333031) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1129185 + ... + 1177006.
It is an arithmetic number, because the mean of its divisors is an integer number (13786415776).
Almost surely, 255143333001 is an apocalyptic number.
It is an amenable number.
55143333001 is a deficient number, since it is larger than the sum of its proper divisors (2330103).
55143333001 is a wasteful number, since it uses less digits than its factorization.
55143333001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2330102.
The product of its (nonzero) digits is 8100, while the sum is 28.
Adding to 55143333001 its reverse (10033334155), we get a palindrome (65176667156).
The spelling of 55143333001 in words is "fifty-five billion, one hundred forty-three million, three hundred thirty-three thousand, one".
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