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55143333001 = 239112306191
BaseRepresentation
bin110011010110110011…
…000111110010001001
312021100000220120002201
4303112303013302021
51400413143124001
641155453000201
73661334411461
oct632663076211
9167300816081
1055143333001
1121427a79289
12a82b483061
13527a504a33
142951862ba1
15167b1b0501
hexcd6cc7c89

55143333001 has 4 divisors (see below), whose sum is σ = 55145663104. Its totient is φ = 55141002900.

The previous prime is 55143332971. The next prime is 55143333019. The reversal of 55143333001 is 10033334155.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 55143333001 - 25 = 55143332969 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (55143333031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1129185 + ... + 1177006.

It is an arithmetic number, because the mean of its divisors is an integer number (13786415776).

Almost surely, 255143333001 is an apocalyptic number.

It is an amenable number.

55143333001 is a deficient number, since it is larger than the sum of its proper divisors (2330103).

55143333001 is a wasteful number, since it uses less digits than its factorization.

55143333001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2330102.

The product of its (nonzero) digits is 8100, while the sum is 28.

Adding to 55143333001 its reverse (10033334155), we get a palindrome (65176667156).

The spelling of 55143333001 in words is "fifty-five billion, one hundred forty-three million, three hundred thirty-three thousand, one".

Divisors: 1 23911 2306191 55143333001