Base | Representation |
---|---|
bin | 11001000101001110101010… |
… | …01101001010000110101011 |
3 | 21020021210100100101101122021 |
4 | 30202213111031022012223 |
5 | 24212130424010403303 |
6 | 313145550100005311 |
7 | 14421556363656613 |
oct | 1442472515120653 |
9 | 236253310341567 |
10 | 55155252044203 |
11 | 166352359802a3 |
12 | 622955a390837 |
13 | 24a116c1a224c |
14 | d89758091a43 |
15 | 659aac0a1ebd |
hex | 3229d534a1ab |
55155252044203 has 4 divisors (see below), whose sum is σ = 55183010099560. Its totient is φ = 55127493988848.
The previous prime is 55155252044173. The next prime is 55155252044279. The reversal of 55155252044203 is 30244025255155.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 55155252044203 - 29 = 55155252043691 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 55155252044203.
It is not an unprimeable number, because it can be changed into a prime (55155252044903) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13879024698 + ... + 13879028671.
It is an arithmetic number, because the mean of its divisors is an integer number (13795752524890).
Almost surely, 255155252044203 is an apocalyptic number.
55155252044203 is a deficient number, since it is larger than the sum of its proper divisors (27758055357).
55155252044203 is a wasteful number, since it uses less digits than its factorization.
55155252044203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 27758055356.
The product of its (nonzero) digits is 1200000, while the sum is 43.
Adding to 55155252044203 its reverse (30244025255155), we get a palindrome (85399277299358).
The spelling of 55155252044203 in words is "fifty-five trillion, one hundred fifty-five billion, two hundred fifty-two million, forty-four thousand, two hundred three".
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